Copyright © (C) 2015, Pablo Lamela, Simon Thompson
Authors: Pablo Lamela Seijas (P.Lamela-Seijas@kent.ac.uk), Simon Thompson (S.J.Thompson@kent.ac.uk).
abstract datatype: cluster_dict(Node)
| extract_trivial_clusters/1 | Removes clusters with only one node from the cluster dictionary. |
| get_cluster_for_node/2 | Finds the cluster that has the Node in the ClusterDict. |
| growing_map_fold/3 | Mapfolds a function through a clusters dictionary. |
| merge_cluster/2 | Adds a Cluster to the ClusterDict and merges the new Cluster with the clusters with common nodes in ClusterDict. |
| new/0 | Creates a new empty cluster dictionary. |
| show_cluster_dict/1 | Returns a more readable version of custer dictionaries. |
| show_cluster_dict/2 | Returns a more readable version of custer dictionaries and takes a function that is suppoused to make the nodes in the clusters more readable. |
extract_trivial_clusters(Cluster_dict::cluster_dict(NodeType)) -> {[cluster:cluster(NodeType)], cluster_dict(NodeType)}
Removes clusters with only one node from the cluster dictionary. It returns a list with the removed clusters.
get_cluster_for_node(Node::N, Cluster_dict::cluster_dict(N)) -> {ok, Cluster::cluster:cluster(N)} | error
Finds the cluster that has the Node in the ClusterDict.
growing_map_fold(Fun::fun((cluster:cluster(N), Acc) -> {[cluster:cluster(N)], none | cluster:cluster(N), Acc}), Acc, Cluster_dict::cluster_dict(N)) -> {cluster_dict(N), Acc}
Mapfolds a function through a clusters dictionary. As opposed to the
traditional mapfold, this one expects an extra element in the
returned tuple, (the first one), which specifies which new clusters
must be map_folded later, (in addition to the original ones
from the cluster dictionary). The updated cluster (second element of
the tuple returned by the function), can be the atom none, this
means that the Cluster will not be in the resulting list.
merge_cluster(Cluster::cluster:cluster(N), ClusterDict::cluster_dict(N)) -> cluster_dict(N)
Adds a Cluster to the ClusterDict and merges the new Cluster with the clusters with common nodes in ClusterDict.
new() -> cluster_dict(any())
Creates a new empty cluster dictionary.
show_cluster_dict(Clus::cluster_dict(term())) -> #{}
Returns a more readable version of custer dictionaries. This is done by transforming dicts and sets into lists.
show_cluster_dict(Fun::fun((NodeType) -> any()), Cluster_dict::cluster_dict(NodeType)) -> #{}
Returns a more readable version of custer dictionaries and takes a function that is suppoused to make the nodes in the clusters more readable. This is done by transforming dicts and sets into lists and by applying the supplied function to the nodes.
Generated by EDoc, Nov 5 2015, 16:30:18.